If perimeter of a rhombus is 100 cm and length of one diagonal is 48 c

1.	If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, what is the area of the quadrilateral?
Answer» Answer: The area of QUADRILATERAL is 336 cm². Step-by-step EXPLANATION: A rhombus has four EQUAL SIDES. The perimeter of a rhombus is 100 cm. $4a=100$ $a=25$ The measure of each side is 25. $4a^2=d_1^2+d_2^2$ Where, a is side length and d₁ and d₂ are diagonals. $4(25)^2=(48)^2+d_2^2$ $2500=2304+d_2^2$ $d_2=\sqrt{2500-2304}$ $d_2=14$ The area of rhombus is $A=\frac{1}{2}(d_1d_2)$ $A=\frac{1}{2}\times 48\times 14$ $A=336$ Therefor the area of quadrilateral is 336 cm².