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If p2x2 + (p2 + q2)x + q2 = 0 has equal roots, then p2– q2 is equal to :(a) – 2q² (b) 2q² (c) 0 (d) -1 |
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Answer» Answer: C) 0 Step-by-step explanation: Equal ROOTS BASICALLY MEANS Discriminant D=0 This implies b^2-4ac=0 Here, b=p^2+q^2 a=p^2 c=q^2 (p^2+q^2)^2=4(p^2)(q^2) On solving, p^2-q^2=0 Thank U |
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