If p(x) =(x sq+1sq)+100=0is a quadratic equation

1.	If p(x) =(x sq+1sq)+100=0is a quadratic equation
Answer» Answer: The GIVEN EQUATION is quadratic. Step-by-step explanation: ACCORDING to the question, p(X)=( $x^{2}$ + $1^{2}$ )+100=0 $x^{2}$ +1+100=0 $x^{2}$ +101=0 Since the degree of the given equation is 2,the given equation is quadratic. Hope it helps..

Answer»

Answer:

The GIVEN EQUATION is quadratic.

Step-by-step explanation:

ACCORDING to the question,

p(X)=( $x^{2}$ + $1^{2}$ )+100=0

$x^{2}$ +1+100=0

$x^{2}$ +101=0

Since the degree of the given equation is 2,the given equation is quadratic.

Hope it helps..

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If p(x) =(x sq+1sq)+100=0is a quadratic equation​

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If p(x) =(x sq+1sq)+100=0is a quadratic equation