p(x)+p(-x) =x+5-x+5=10

p(x)=x+5......eq 1p(_x)=x_5.........eq 2on adding eq 1 and 2 we get, 0

p(x)=x+5;q(-x)= -x+5; then p(x)+q(-x)=x+5+(-x+5)=x+5-x+5=10

answer will be zero bcoz the sign changes in p(-x)

the answer is 0 because p(x) + p(-x) is equal to 0

P(x) + P(-x), Here, P(x) =x+5so, x+5+[-(x+5) ]=x+5-x-5=0

If P(x)=x+5 then P(-x) =-x+5 Therefore, P(x)+P(-x) =x+5-x+5= 10.

just put -ve in x term i.e. we get 10 after adding x+5 and -x+5

P(x) =x+5Then,P(-x)=-(x+5)P(-x)=-x-5Now,P(x)+p(-x)=x+5-x-5=0

right answer is 10.if sine change for that only the sine change of the value of the x not the value of total function

p(x)=x+5 p(-x)=-x+5 Then p(x)+p(-x) = x+5-x+5= 10

if p(x)=(x+5),. then p(-x)=(-x-5)now add p(x)&p(-x)we getx+5-x-5=0

p(x)+p(-x)p(x)-p(x)px-px0

p(x)=x+5 p(-x)=-x+5adding both we get 10

the correct answer is zero

X+5 -x+5=10 so this is the answer of this question

p(x)+p(-x)p(-5)+p(+5)2p

if P(x)= x+5 P(x) +P(-x) x+5+x-5value is 2x

2p are the right answer

p(x)+p(-x)=x+5-x+5=10

p(x)=x+5x=-5 y(x)=p(x)+p(-x) =p(-5)+p(+5)so -5 or +5 is cancel so that the answer is=20

p(X)+p(-X) = (X+5)+(-(X+5)=0

p(-x)+p(x)=-x+5+x+5=10

x+5-x+5 = 10

given that p(x) = x+5so just put the value in the equation given

(x+5) + (-x+5) = 10

p(x)+p(-x)=x+5-x-5=0

the correct answer is 10

P (x)=x+5,so P (-x)=-x+5,now P (x)+P(-x)=x+5+(-x+5)=x+5-x+5=10

the answer is 0

The anser to the above question is 10

p(x)=-5x=-5p(-5)+p(-(-5))-5p+5p=0

p(x)+p(-x )= X+5-x-5=0

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p(x)=x+5p(-x) =-(x+5) = -x-5

p(x)+p(-x) =x+5+(-x-5) =x+5-x-5 =0

if p(x) =x+5p(-x) =-x+5p(x)+p(-x) =x+5-x+5=10

(x+5)+(-x+5) = 5+5 = 10

p(x)=x+5then p(-x)=-x+5p(x)+p(-x)=x+5-x+5 =10

10 is the correct answer for this

x+5=0x= -5

x-5=0x=5

p(5)+p(-(-5))5+5=10

p(-5)+p(5)=-5p+5p = 0

your answer is zero only zero

x+5-x-5=0 . 0 is the answer

the answer of this question will be 10

The answer will be 10. Put - x instead of x in 2nd term.

P(x) +p

x+5-x+5=10 so the answer is 10

given, p(x) = x + 5then, p(-x)= -x + 5p(x)+p(-x)= x + 5 - x + 5 = 10

p(x)=x+5p(-x)It can also be written as -pxTherefore p(-x)=-(x+5)=-x-5Therefore p(x)+p(-x)=x+5+(-x-5)=x+5-x-5=0

in above problem if p(x)=x+5 then p(-x)=-x+5 and hence p(x)+p(-x)=x-x+10=10

Bhai aapk x ki jagah -5 rakhi aapka answer aa jayega

10 is the absolutely correct answer

P(X) = X + 5 & P(-X) = -X+5 so adding it we get 10 ans