If p(x)=x^3-ax^2+bx+3 leaves a remainder -19 whendivided by (x+2) and a remainder 17 when divided by (x-2), then prove that a+b=6

If p(x)=x^3-ax^2+bx+3 leaves a remainder -19 whendivided by (x+2) and

1.	If p(x)=x^3-ax^2+bx+3 leaves a remainder -19 whendivided by (x+2) and a remainder 17 when divided by (x-2), then prove that a+b=6
Answer» If p(x)=x^3-ax^2+bx+3 leaves a remainder -19 whendivided by (x+2) and a remainder 17 when divided by (x-2), then prove that a+b=6