If p(x)=x^1+x2+ax+115 is exactly divisible by(x+5) then a=? please ans

1.	If p(x)=x^1+x2+ax+115 is exactly divisible by(x+5) then a=? please answer this question
Answer» ONG>Step-by-step EXPLANATION: =)x^2 + x2 + ax + 115 =) x+5=0 =) x= -5 By fitting the value =) (-5)^1 + (-5)^2 + (-5a) +115= 0 =) -5 + 25-5a + 115 = 0 =) 135 - 5a = 0 =) -5a = 135 =) a = 135/-5 a = -27 THIS IS THE ANSWER

If p(x)=x^1+x2+ax+115 is exactly divisible by(x+5) then a=? please answer this question

Answer» ONG>Step-by-step EXPLANATION:

=)x^2 + x2 + ax + 115

=) x+5=0

=) x= -5

By fitting the value

=) (-5)^1 + (-5)^2 + (-5a) +115= 0

=) -5 + 25-5a + 115 = 0

=) 135 - 5a = 0

=) -5a = 135

=) a = 135/-5

a = -27

THIS IS THE ANSWER

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If p(x)=x^1+x2+ax+115 is exactly divisible by(x+5) then a=? please answer this question​

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If p(x)=x^1+x2+ax+115 is exactly divisible by(x+5) then a=? please answer this question