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if p times th p th term of an AP is equal to q times the qth term .show that it's (p+q) th term is zero |
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Answer» pth= a+( p-1)d (p+q)= a+ (p+q-1)d=? as p×pth=q×qth p(a+(p-1)d)= q{a+ (q-1)d} a(p-q)= d(q^2-p^2-q+p) a= d{ (q+p)(q-p)+ (q-p)}/p-q=d(-q-p+1)substituting it in 3RD we haved(p+q-1) - (p+q-1)d =0 |
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