1.

If p (t)=(t) (t-1) (t+1)then find p(o),p(1)andp(2)​

Answer»

<P>Answer:

i)Valueofp(1)

= ( 1 - 1 )( 1 + 1 )=(1−1)(1+1)

= 0 \TIMES 2=0×2

\green { = 0 }=0

ii ) \red{VALUE \: of \: p(0) }ii)Valueofp(0)

= ( 0 - 1 )( 0 + 1 )=(0−1)(0+1)

= (-1) \times 1=(−1)×1

\green { = -1 }=−1

Therefore.,

\red{ Value \: of \: p(1) } \green { = 0}Valueofp(1)=0

\red{ Value \: of \: p(0) } \green { = -1}Valueofp(0)=−1

Step-by-step EXPLANATION:

p(1) = (1-1) (1+1)

=0×2

= 0

p(o) =(0-1) (0+1)

=-1×1

= -1


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