If P(Q−r)x2+Q(r−P)x+r(P−Q)=0 has equal roots then 2Q=(where P,Q, – InterviewSolution

1.	If P(Q−r)x2+Q(r−P)x+r(P−Q)=0 has equal roots then 2Q=(where P,Q,r ϵ R)
Answer» $I f P (Q - r) x^{2} + Q (r - P) x + r (P - Q) = 0 h a s e q u a l r o o t s t h e n \frac{2}{Q} = (w h e r e P, Q, r ϵ R)$

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