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If`p > q >0a n dp r |
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Answer» since `p, q gt 0`, we have `pq gt 0` `tan^(-1) (p -q)/(1 + pq) = tan^(-1) p - tan^(-1) q`....(i) Since `qr gt -1`, we have `tan^(-1) (q -r)/(1 + qr) = tan^(-1) q - tan^(-1) r`...(ii) Since `pr lt -1 and r lt 0`, we have `tan^(-1) (r - p)/(1 + rp) = pi + tan^(-1) t - tan^(-1) p`....(iii) On adding Eqs. (i), (ii), and (iii), we get `tan^(-1) (p -q)/(1 + pq) + tan^(-1) (q - r)/(1 + qr) + tan^(-1) (r - p)/(1 + rp) = pi` |
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