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If p (9a-2,-2-b) divides the line segment joining A(3a+1,-3)and B(8a,3) in the ratio 3:1? then find the value of a and b? |
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Answer» P(9a-2,b) = (x,y)A(3a+1.-3) = (x1,y1)B(8a,5) = (x2,y2)Ratio (m1,m2) = 3,1 x = m1*x2 + m2*x1 --------------------- m1 + m29a-2 =3*8a +1*3a+1 ----------------- 3 + 19a-2 = 24a + 3a + 1 ---------------- 436a - 8 = 27a + 136a - 27a= 1+ 89a = 9a = 9 ----- 9a = 1 Now, y = m1*y2 + m2*y1 --------------------- m1 + m2-b = 3*5 + 1 * -3 ---------------- 4-b = 15 - 3 -------- 4-b = 12/4-b = 3b = -3 Therefore a = 1, b = -3 |
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