1.

If p=99 then 3√p(p²+3p+3)+1

Answer»

<P>Step-by-step EXPLANATION:

\sqrt[3]({p }^{3}  + 3 p {}^{2}  + 3p   + <klux>1</klux>)

\sqrt[3]{(p + 1) {}^{3} }

= P + 1

= 99 + 1

= 100.



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