1.

If p= -3,q=-1and r=2,find the value of 3p²q²r²-2pqr+7​

Answer»

★ Concept :-

  • While solving algebraic expressions, MAKE sure that VARIABLES are at left side.

  • Variables are the alphabets which are used in a algebraic expression.

  • Constants are the numbers with are used in algebraic expressions.

Answer :-

  • 3p²q²r²-2pqr+7 = 127.

Given :-

  • p = -3,
  • Q = -1
  • r = 2

To find :-

  • Find the value of 3p²q²r²-2pqr+7?

Solution :-

➜ 3p²q²r²-2pqr+7

➜ 3(-3)²(-1)²(2)² - 2(-3×1×2) + 7

➜ 3(9)(1)(4) - 2(-6) + 7

➜ 108 + 12 + 7

➜ 108 + 19

➜ 127

Hence, The value of 3p²q²r²-2pqr+7 = 127.

Know more :-

Follow these , While solving any algebraic expressions.

  • ( + ) × ( − ) = ( − )
  • ( + ) × ( + ) = ( + )
  • ( - ) × ( + ) = ( - )
  • ( - ) × ( - ) = ( + )


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