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If p-1, p+3, 3p-1 are in A.P. then p is equal to :(A) 4(B) -4(C) 2 |
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Answer» For APnth term = a + (n-1)d For given APa = p-1, d = (p+3 - p +1) =4 For 3rd term3p - 1= (p-1) + (3-1)43p - p = 2*42p = 8p = 4 Value of p = 4 |
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