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If }\operatorname{cos}A=n\operatorname{cos}B and }\operatorname{sin}A=m\operatorname{sin}B then show that }(m^2-n^2)\operatorname{sin}^2B=1-n^2

Answer» If }\operatorname{cos}A=n\operatorname{cos}B and }\operatorname{sin}A=m\operatorname{sin}B then show that }(m^2-n^2)\operatorname{sin}^2B=1-n^2


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