Saved Bookmarks
| 1. |
If }\operatorname{cos}A=n\operatorname{cos}B and }\operatorname{sin}A=m\operatorname{sin}B then show that }(m^2-n^2)\operatorname{sin}^2B=1-n^2 |
| Answer» If }\operatorname{cos}A=n\operatorname{cos}B and }\operatorname{sin}A=m\operatorname{sin}B then show that }(m^2-n^2)\operatorname{sin}^2B=1-n^2 | |