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If one zeroes of the polynomial (k-1)x²+kx+1 is -3.What is the value of k |
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Answer» Answer: Remainder THEOREM: p(X) = (k-1)x²+kx+1 p(-3) = 9(k-1) -3k+1 0 = 9(k-1) -3k+1 -1 = 9K -9 -3k 9 = 6k k = 9/6 = 3/2 |
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