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If one zero of the quadratic polynomial (k – 1)x2 – kx + 1 is -4, then the value of k is(a) \(\frac{-5}4\) (b) \(\frac{5}4\) (c) \(\frac{-4}3\) (d) \(\frac{4}3\) |
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Answer» Since –4 is a zero of (k – 1) x2 + kx + 1, we have: (k – 1) × (-4)2 + k × (-4) + 1 = 0 ⇒ 16k – 16 – 4k + 1 = 0 ⇒ 12k – 15 = 0 ⇒ k = \(\frac{15}{12}\) ⇒ k = \(\frac{5}{4}\) |
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