If one zero of the quadratic polynomial f(x)=4x^2-8kx-9 is negative of

1.	If one zero of the quadratic polynomial f(x)=4x^2-8kx-9 is negative of the other find the value of k
Answer» Answer: k = 0. Step-by-step EXPLANATION: GIVEN : $\large \text{$f(<klux>X</klux>)=4x^2-8kx-9$}$ And one zero is negative of the other. We have to find value of k. $\large \text{Let one zero be $\alpha $ so other will be $-\alpha $}$ We know sum of two zero = - b / a where b is coefficient of x and a is coefficient of $x^2$ Putting VALUES here we GET $\large \text{$\alpha-\alpha=\dfrac{-8k}{4}$}\\\\\\\large \text{$0=-2k$}\\\\\\\large \text{$k=0$}$ Thus we get k = 0.