1.

if one zero of the polynomial 2xsquare – 5x – (2k+1 ) is twice the other, then find both the zeroes and the value of k

Answer»

hy\\friend


LET, p(X)=2x²-5x-(2k+1)--------(1)

Also let, α be one ROOT of (1).

Then the other root will be 2α.


α+2α=-(-5)/2


⇒ 3α=5/2


⇒ α=5/6


Again, α×2α=-(2k+1)/2


⇒ 2α²=-(2k+1)/2


⇒ -(2k+1)/2=2×(5/6)²


⇒ -(2k+1)=4×25/36


⇒ -2k-1=25/9


⇒ -2k=25/9+1


⇒ -2k=34/9


⇒  k=-34/9×1/2


⇒ k=-17/9 Ans.



thankyou\\brainly star


Discussion

No Comment Found

Related InterviewSolutions