1.

If one zero of 3x2 – 8x + k be the reciprocal of the other, then k = ? (a) 3 (b) -3(c) \(\frac{1}3\) (d) \(\frac{-1}3\)

Answer»

(a) k = 3 

Let α and \(\frac{1}α\) be the zeroes of 3x2 – 8x + k. 

Then the product of zeroes = \(\frac{k}3\)

⇒ α × \(\frac{1}α\) = \(\frac{k}3\)

⇒ 1 = \(\frac{k}3\)

⇒ k = 3


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