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If one root of the quadratic equation 3 y^{2}-k y+8=0 \text { is } \frac{2}{3} then find the value of k. |
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Answer» as 2/3 is a root hence it will satisfy the equationhence3*(2/3)^2-k*(2/3)+8=03*4/9-2k/3+8=04/3-2k/3+24/3=04-2k+24=028-2k=0k=14 |
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