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If one of the zeroes of the quadratic polynomial P(x) = 14x²- 42k²- 9 is negative of the other find the value of k

Answer» HEY there..!!

Here's your SOLUTION..

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let \: one \: zero = \alpha \\ other \: zero = - \alpha \\ \\ sum \: of \: zeroes = \alpha - \alpha = 0 \\ product \: of \: zeroes = \alpha \times ( - \alpha ) = { - \alpha }^{2} \\ \\ so \: - b \div a = 0 \\ = > 42 {k}^{2} \div 14 = 0 \\ = > 42 {k}^{2} = 0 \\ = > {k}^{2} = 0 \\ \\ so \: k = 0
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CHEERS..✌

@Rêyaañ11


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