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If one of the zeroes of the quadratic polynomial (k-1)x^2+1 is -3 |
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Answer» ONG>ANSWER: Step-by-step explanation: (k - 1)x² + KX + 1.
SINCE one of the zeroes is -3,so when we substitute -3 in the polynomial we get 0
(k - 1) (-3)² + k (-3) + 1 = 0
=> 9k - 9 - 3k + 1 = 0
=> 6k - 8 = 0
=> 6k = 8
=> k = 8/6 = 4/3
Thus the value of k = 4/3. |
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