1.

If one of the zeroes of the quadratic polynomial (k-1)x2+ kx +1 is -3, then the value of k is (a) (b) - (c) (d)-​

Answer»

ANSWER:

p(x) = (k-1)×2 + kx +1

then

p(-3) = (k-1)×2 + k×(-3) + 1

for zeroes of a polynomial

p(x)=0

0 = (k-1)×2 -3k +1

0= 2k -2 -3k +1

0 = -1 -k

1 = -k

so,

k = -1 answer


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