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If one of the zeroes of the quadratic polynomial (-1) 2 + kx + 1 is-3, then the value of kis. |
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Answer» Given p(x) = (k -1)x² + kx + 1 As (-3) is zero then p(-3) = 0 So, p(-3) = (k -1) (-3)² + k × (-3) + 1 = 0 9( k -1) - 3k + 1 = 0 9k - 9 - 3k + 1 = 0 6k = 8 k = 4/3 |
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