1.

If one of the zeroes of the quadratic polynomial (-1) 2 + kx + 1 is-3, then the value of kis.

Answer»

Given p(x) = (k -1)x² + kx + 1

As (-3) is zero then p(-3) = 0

So,

p(-3) = (k -1) (-3)² + k × (-3) + 1 = 0

9( k -1) - 3k + 1 = 0

9k - 9 - 3k + 1 = 0

6k = 8

k = 4/3



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