If one of the zeroes of (P -1) x^2 + px + 1 is -3 find the value of p�

1.	If one of the zeroes of (P -1) x^2 + px + 1 is -3 find the value of p
Answer» Answer: Just plug x=-3 into the polynomial and set it equals to zero cause x=-3 will SATISFY the expression, so (P-1)(-3)^2 -3P +1=0 9P-9 -3P+1=0=0 6P=8 P=8/6 P=4/3*

If one of the zeroes of (P -1) x^2 + px + 1 is -3 find the value of p

Answer»

Answer:

Just plug x=-3 into the polynomial and set it equals to zero cause x=-3 will SATISFY the expression, so

(P-1)*(-3)^2 -3P +1=0

9P-9 -3P+1=0=0

6P=8

P=8/6

P=4/3

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If one of the zeroes of (P -1) x^2 + px + 1 is -3 find the value of p​

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If one of the zeroes of (P -1) x^2 + px + 1 is -3 find the value of p