If one of the lines my^2+(1-m)^2xy-mx^2=0 is a bisector of angle betwe

1.	If one of the lines my^2+(1-m)^2xy-mx^2=0 is a bisector of angle between the lines xy=0 then m =
Answer» Step-by-step EXPLANATION: ANGLE BISECTORS of xy=0 are x+y=0 and x=y my 2 +xy−m 2 xy−mx 2 =0 ∴y(my+x)−mx(my+x)=0 ∴(y−mx)(my+x)=0 Comparing y−mx=0 and my+x=0 with y=x and y=−x, we GET m=±1

If one of the lines my^2+(1-m)^2xy-mx^2=0 is a bisector of angle between the lines xy=0 then m =

Answer»

Step-by-step EXPLANATION:

ANGLE BISECTORS of xy=0 are x+y=0 and x=y

+xy−m

xy−mx

∴y(my+x)−mx(my+x)=0

∴(y−mx)(my+x)=0

Comparing y−mx=0 and my+x=0 with y=x and y=−x, we GET m=±1

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If one of the lines my^2+(1-m)^2xy-mx^2=0 is a bisector of angle between the lines xy=0 then m =​

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If one of the lines my^2+(1-m)^2xy-mx^2=0 is a bisector of angle between the lines xy=0 then m =