1.

If one of the diameters of the circle, given by the equation, x2+y2−4x+6y−12=0, is a chord of a circle S, whose centre is at (–3, 2), then the radius of S is:

Answer»

If one of the diameters of the circle, given by the equation, x2+y24x+6y12=0, is a chord of a circle S, whose centre is at (–3, 2), then the radius of S is:




Discussion

No Comment Found