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If one number is selected from first 70 natural numbers, find the probability that the number is a solution of x^2 + 2x > 4....Plz don't spam or I curse you for 13 Years of Badluck.​

Answer»

Step-by-step explanation:

Given If one NUMBER is selected from first 70 natural numbers, find the PROBABILITY that the number is a solution of x^2 + 2x  > 4

  • Now probability is given by probability = number of FAVOURABLE outcomes / total number of possible outcomes.
  • Now a number is selected at random from first natural numbers.
  • So we get total number of outcomes will be 70
  • Favourable outcomes will be  
  • So x^2 + 2x > 4
  • Now TAKING 1 we get  1^2 + 2 (1) = 3 < 4
  •                                    2^2 + 2(2) = 8 > 4
  • So all other numbers up to 70 will be greater than 4. So we have                70 – 1 = 69
  • So total number of favourable outcomes will be 69
  • Therefore probability will be 69 / 70

Reference link will be

brainly.in/question/8619616



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