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If one end of the a diameter of the circle `2x^2+2y^2-4x-8y+2=0`is (3, 2), then find the other end of the diameter. |
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Answer» Correct Answer - (-1,2) The center of the given circle is (1,2). Let (alpha,beta)` be the other end. Then, `=2 sqrt(g^(2)-c)=2 sqrt(25-9)=8` |
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