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If o is a complex cube root of unity, then the value of 099 +0100 +0101 is:(A)/-1(B) 1(C) 0(D) 3 |
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Answer» There are a total of three cube roots of unity which are as follows: Cube Root of Unity Value Nature of Cube Root 1 Real −½ + i √(3/ 2) Complex −½ – i √(3/ 2) Complex Here, a = 1 is the real cube root of unity while a = – ½ + i √(3/ 2) and a = – ½ – i √(3/ 2) are the IMAGINARY or complex cube roots of unity. How to Find Cube Root of Unity Values (Derivation)? Suppose the cube root of 1 is “a”, i .e 3√1 = a. According to the general cube roots definition, a3 = 1 or a3 – 1 = 0 (a3 – b3) = (a – b) ( a2 + AB + b2) Now, (a3 – 13) = 0 or (a – 1)( a2 + a + 1) = 0 Therefore, a = 1 or ( a2 + a + 1) = 0 By using quadratic roots formula for the above equation, we get; a = [(-1) ± √(12-4.1.1)]/2 = [-1 ± √-3]/2 = -1/2 ± i√(3)/2 Therefore, the three cube roots of unity are: 1, -1/2+i√(3)/2, -1/2 – i√(3)/2 |
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