If number of points of discontinuity of f(x)=sgn(cos5x) is equal to the number of points of non- differentiability of g(x) = {n + m sin x} where x ∈ (0,π), n, m ∈ I, then value of m is (where, {x} denotes fractional part of x and sgn(x) denotes signum function of x)

If number of points of discontinuity of f(x)=sgn(cos5x) is equal to th

1.	If number of points of discontinuity of f(x)=sgn(cos5x) is equal to the number of points of non- differentiability of g(x) = {n + m sin x} where x ∈ (0,π), n, m ∈ I, then value of m is (where, {x} denotes fractional part of x and sgn(x) denotes signum function of x)
Answer» If number of points of discontinuity of $f (x) = s g n (cos 5 x)$ is equal to the number of points of non- differentiability of g(x) = {n + m sin x} where $x \in (0, π), n, m \in I$ , then value of $m$ is (where, {x} denotes fractional part of x and sgn(x) denotes signum function of x)