1.

If npr = 240, nCr = 120 find n and r.

Answer»

Given npr = 240, nCr = 120 

w.k.t ncr = \(\frac{^nP_r}{r!}\)

∴ r! = \(\frac{240}{120}\) = 2

r! = 2! ⇒ r= 2.



Discussion

No Comment Found