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If npr = 240, nCr = 120 find n and r. |
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Answer» Given npr = 240, nCr = 120 w.k.t ncr = \(\frac{^nP_r}{r!}\) ∴ r! = \(\frac{240}{120}\) = 2 r! = 2! ⇒ r= 2. |
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