If NaCl is doped with 10−4 mol% SrCl2, the concentration of cation v – InterviewSolution

1.	If NaCl is doped with 10−4 mol% SrCl2, the concentration of cation vacancies will be (NA=6.02×1023mol−1)
Answer» If NaCl is doped with $10^{- 4} m o l % S r C l_{2}$ , the concentration of cation vacancies will be $(N_{A} = 6.02 \times 10^{23} m o l^{- 1})$

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