If n+l=6; m=0,±1 and s=±12 then what is the maximum number of electr – InterviewSolution

1.	If n+l=6; m=0,±1 and s=±12 then what is the maximum number of electrons of an atom of cesium that will have the above set and combination of quantum numbers?(Atomic number of cesium is 55)
Answer» If $n + l = 6$ ; $m = 0, \pm 1$ and $s = \pm \frac{1}{2}$ then what is the maximum number of electrons of an atom of cesium that will have the above set and combination of quantum numbers?(Atomic number of cesium is 55)

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