If n is odd, then 1+3+5+7+.....+ to n terms is equal to (a) (n2+1) (b) – InterviewSolution

1.

If n is odd, then 1+3+5+7+.....+ to n terms is equal to (a) (n2+1) (b) (n2−1) (c) n2 (d) (2n2+1)

Answer»

If $n$ is odd, then $1 + 3 + 5 + 7 + . . . . . +$ to $n$ terms is equal to

(a) $(n^{2} + 1)$

(b) $(n^{2} - 1)$

(c) $n^{2}$

(d) $(2 n^{2} + 1)$

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