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If n is greater than 1, the roots of (z+1)n=zn lies on a(a) circle(b) ellipse(c) hyperbola(d) straight line |
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Answer» It will lies on straight line. Explanation: Any solution to the equation zn = (z+1)n satisfies |z| = |z+1| i.e. the point is equidistant from (0,0) and (-1,0). This means it lies on the perpendicular bisector of the line joining (0,0) and (-1,0) i.e. x = -1/2 or 2x+1 = 0. |
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