If n (A ∪ B) =50 , n (A) =15 , n(B) = 21 , n(C) = 18 , n (A ∩ B) =

1.	If n (A ∪ B) =50 , n (A) =15 , n(B) = 21 , n(C) = 18 , n (A ∩ B) = 5 , n (B ∩ C) =6 , n(C ∩ A ) = 7 , then n (A ∩ B ∩ C) =
Answer» N B NC)=n(A)+n(B)+n(C)-n(A U B U C) Step-by-step explanation: more CALCULATE yourself if not able to then TELL me

If n (A ∪ B) =50 , n (A) =15 , n(B) = 21 , n(C) = 18 , n (A ∩ B) = 5 , n (B ∩ C) =6 , n(C ∩ A ) = 7 , then n (A ∩ B ∩ C) =

Answer» N B NC)=n(A)+n(B)+n(C)-n(A U B U C)

Step-by-step explanation:

more CALCULATE yourself if not able to then TELL me

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If n (A ∪ B) =50 , n (A) =15 , n(B) = 21 , n(C) = 18 , n (A ∩ B) = 5 , n (B ∩ C) =6 , n(C ∩ A ) = 7 , then n (A ∩ B ∩ C) =​

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If n (A ∪ B) =50 , n (A) =15 , n(B) = 21 , n(C) = 18 , n (A ∩ B) = 5 , n (B ∩ C) =6 , n(C ∩ A ) = 7 , then n (A ∩ B ∩ C) =