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If n = 23 ✕ 34 ✕ 54 ✕ 7, then the number of consecutive zeros in n, where n is a natural number, is(a) 2(b) 3(c) 4(d) 7 |
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Answer» If n = 23 ✕ 34 ✕ 54 ✕ 7, then the number of consecutive zeros in n, where n is a natural number, is (a) 2 (b) 3 (c) 4 (d) 7 |
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