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If more air is pushed in a soap bubble, the pressure in it (a) decreases (b) increases(c) remains same (d) becomes zero. |
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Answer» (a) decreases Explanation: The excess pressure (w.r.t. atmospheric pressure) inside a soap bubble is given as P'-P = 4S/R, {where P'-pressure inside the bubble, P- atmospheric pressure} It is clear that the excess pressure inside is inversely proportional to the radius. As more air is pushed in a soap bubble its radius increases hence the excess pressure inside decreases. |
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