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If momentum `(P)`, area `(A)` and time `(7)` are taken to be fundamental quntities, then power has the dimensional formula.A. `(P^(1)A^(-1)T^(1))`B. `(P^(2)A^(1)T^(1))`C. `(P^(1)A^(-1//2)T^(1))`D. `(P^(1)A^(1//2)T^(-2))` |
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Answer» Correct Answer - D [Power]=[(work)/(time)]`=`[(forcexxlength)/(time)] `=[(momentumxxsqrtarea)/(time)^(2)]=[P^(1)A^(1//2)T^(-2)]` |
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