If momentum is increased by 20% then K.E increases by? plz explain plz

1.	If momentum is increased by 20% then K.E increases by? plz explain plzzzzz
Answer» HI Mate!!! K.E = p² / 2M {( K.E )f -( K.E )I/ K.E)I. } ×100 =. ( pf² - pi² / pi² ) ×100 Pf= 100+20. PI = 100. CHANGE in K.E = ( 120)² - (100)

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If momentum is increased by 20% then K.E increases by? plz explain plzzzzz

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