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if mole fraction of water in aqueous solution of cacl2 is 0.9 what is the mass of solution???? ( molar mass of cacl2 is 111) |
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Answer» As per the FORMULA X1+X2= 1 Here X1 REPRESENTS MOLE fraction of solvent and X2 represents mole fraction of solute X1 =0.9 then X2=0.1 If mass of water is 100g and molar mass is 18 Moles 1=100/18=5.55 X1=moles 1/total moles Total moles = 5.55/0.9=6.17 X2= moles 2/ total moles Moles 2=0.1×6.17=0.617 Moles 2= weight /molar mass Weight=0.617×111=68.5g I hope this HELPS ( ╹▽╹ ) |
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