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If mass of `U^(235)=235.12142 a.m.u.`, mass of `U^(236) =236.1205 amu`, and mass of neutron `=1.008665 am u`, then the energy required to remove one neutron from the nucleus of `U^(236)` is nearly about.A. zeroB. 6.5 MeVC. 75 MeVD. 1 cV |
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Answer» Correct Answer - B Given, `m(U^(215))=235.121420`amu `m(0^(n^(1)))=1.008665`amu `m(U^(236))=236.123050`amu Mass defect `triangle m=m(U^(235))+m(0^(n^(1)))-m(U^(236))` `=235.121420+1.008665-236.123050` `triangle m=0.007`amu Energy required to remove one neutron `=0.007xx931`MeV `=6.517`MeV`=6.5`MeV |
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