1.

If mass of neutron is assumed to half of its original value. Whereas that of proton is assumed to be twice of its original value, then the atomic mass of ._(6)^(14C will be:

Answer»

same
14.28% more
14.28% less
28.56% less

Solution :In the ISOTOPE `._(6)^(14)C`: number of protons=6
Number of neutrons=8
New atomic MASS will be `=2xx6+(1)/(2)xx8=16`
% Increase in mass `=(16-14)/(14)xx100=14.28%`.


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