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If /m sece + n tane and k = n sece + m tan0, then(1) 12 k2 = m2 + n2m2 n2(2) 12 K2 = m2 + n2(3) 12 K2= m2 - n2(4) 12k2=m2 - n2sin8A is80 |
| Answer» If /m sece + n tane and k = n sece + m tan0, then(1) 12 k2 = m2 + n2m2 n2(2) 12 K2 = m2 + n2(3) 12 K2= m2 - n2(4) 12k2=m2 - n2sin8A is80 | |