1.

if `m_p` and `m_(alpha)` are masses of proton and `alpha-`particles find ratio of momentum of a proton and an `alpha-`particle which are accelerated fromr est by a potential difference of 200 V.A. `(m_(p))/(2m_(alpha))`B. `(2m_(alpha))/(m_(p))`C. `(sqrt((m_(p))/(2m_(alpha))))`D. `sqrt((2m_(p))/(m_(alpha)))`

Answer» Correct Answer - C
`QV=(1)/(2)mv^(2)`
`thereforev=sqrt((2QV)/(m))`
`thereforev_(P)=sqrt((2QV)/(m_(P)))` or `V_(alpha)=sqrt((2xx2QV)/(m_(alpha)))`
`m_(P).V_(P)=sqrt(2QV.m_(P))` & `m_(alpha).v_(alpha)=sqrt(4QV.m_(alpha))`
`therefore` ratio `=sqrt((m_(P))/(2m_(alpha)))`


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