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if `m_p` and `m_(alpha)` are masses of proton and `alpha-`particles find ratio of momentum of a proton and an `alpha-`particle which are accelerated fromr est by a potential difference of 200 V.A. `(m_(p))/(2m_(alpha))`B. `(2m_(alpha))/(m_(p))`C. `(sqrt((m_(p))/(2m_(alpha))))`D. `sqrt((2m_(p))/(m_(alpha)))` |
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Answer» Correct Answer - C `QV=(1)/(2)mv^(2)` `thereforev=sqrt((2QV)/(m))` `thereforev_(P)=sqrt((2QV)/(m_(P)))` or `V_(alpha)=sqrt((2xx2QV)/(m_(alpha)))` `m_(P).V_(P)=sqrt(2QV.m_(P))` & `m_(alpha).v_(alpha)=sqrt(4QV.m_(alpha))` `therefore` ratio `=sqrt((m_(P))/(2m_(alpha)))` |
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