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If m is the A.M. of two distinct real numbers `l and n(l, n>1) and G_1, G_2 and G_3`, are three geometric means between `I and n`, then `G_1^4+2G_2^4+G_3^4` equals-A. `4lmn^(2)`B. `4l^(2)m^(2)n^(2)`C. `4l^(2)mn`D. `4lm^(2)n` |
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Answer» Correct Answer - D We have, `m=(l+n)/(2)` Let be the common ratio of the G.P. l, `G_(1),G_(2),G_(3),n`. Then `n=lr^(4)rArrr=((n)/(l))^(1//4)` `:." "G_(!)=lr=l^(3//4)n^(1//4),G_(2)=lr^(2)=l^(2//4)n^(2//4),G_(3)=lr^(3)=l^(1//4)n^(3//4)`. `rArr" "G_(1).^(4)+2G_(2).^(4)+G_(3).^(4)=l^(3)n+2l^(2)n^(2)+l n^(3)= ln(l+n)^(2)=l n(2m)^(2)=4lm^(2)n`. |
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