1.

If m = -2 and n=2; find the value of:(1) m2 + n2 - 2mn(ii) mn + nm(iv) 2n- 3m(iii) 6m-3 + 4n2​

Answer»

Answer:

1](-2)2+(2)2- 2(-2×2)

-4+4+8

-4+12

+8.....

2](-2×2)+(2×-2)

-4+-4

= 0...



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