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If m = -2 and n=2; find the value of:(1) m2 + n2 - 2mn(ii) mn + nm(iv) 2n- 3m(iii) 6m-3 + 4n2 |
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Answer» Answer: 1](-2)2+(2)2- 2(-2×2) -4+4+8 -4+12 +8..... 2](-2×2)+(2×-2) -4+-4 = 0... |
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