If m_(1) = 3kg and m_2 = 1 kg what is the angular momentum of the system about center of pulley ? The radius of the pulley is 0.3 m and its moment of inertia about its axle is 0.14 kg m^2. The system moves with a linear velocity of 2 m/s on a frictionless horizontal surface ?

If m_(1) = 3kg and m_2 = 1 kg what is the angular momentum of the syst

1.	If m_(1) = 3kg and m_2 = 1 kg what is the angular momentum of the system about center of pulley ? The radius of the pulley is 0.3 m and its moment of inertia about its axle is 0.14 kg m^2. The system moves with a linear velocity of 2 m/s on a frictionless horizontal surface ?
Answer» SOLUTION :`L = m_(1)VR + m_(2)vr+ lv//r = (3+1) xx 2XX 0.3 + 0.14 xx (2//0.3) = 3.33 Js`, (r-radius of PULLEY)